Reply to Re: How Does this work?!
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Yup. Proof:
Let A be the first digit of your number, B be the second digit. Therefore
Your number = 10A + B
End number = 10A + B - A - B = 9A
and A is an integer so the end number will always be a multiple of 9
Let A be the first digit of your number, B be the second digit. Therefore
Your number = 10A + B
End number = 10A + B - A - B = 9A
and A is an integer so the end number will always be a multiple of 9
