PI
PI can't be resolved, or at least not when I was in school. It's 3.14159
There are numbers that are "more" irrational than Pi, like the square root of two.
I know about these features of PI. It isn't a solution to a polynomial function (hey, I can act quite interesting too
) This is called a transcedent number.
What I meant was how many digits does the page contain... how large is it? I've got a 12,7 MB PI-txt on my pc.
About the square root of two. This is a solution to a polynomial function, this one, to be exactly:
x^2 + 2 = 0.
Polynomial functions look like this, by the way:
ax^n + bx^(n-1) + cx^(n-2) + ... + yx + z = 0.
Where x is the var to be found, n is a power of x and a,b,c,y,z are indexes.
) This is called a transcedent number.What I meant was how many digits does the page contain... how large is it? I've got a 12,7 MB PI-txt on my pc.
About the square root of two. This is a solution to a polynomial function, this one, to be exactly:
x^2 + 2 = 0.
Polynomial functions look like this, by the way:
ax^n + bx^(n-1) + cx^(n-2) + ... + yx + z = 0.
Where x is the var to be found, n is a power of x and a,b,c,y,z are indexes.
This is really sad...
Why didn't anyone in there correct me? There are lots of mathematical intelligent human beings here.
x^2 + 2 = 0 is wrong, it should be x^2 - 2 = 0
The solution of the first one is sqrt(2)*I or -sqrt(2)*I if I remember correctly.
Sqrt means square root, in this case.
Why didn't anyone in there correct me? There are lots of mathematical intelligent human beings here.
x^2 + 2 = 0 is wrong, it should be x^2 - 2 = 0
The solution of the first one is sqrt(2)*I or -sqrt(2)*I if I remember correctly.
Sqrt means square root, in this case.
Neither one is wrong. One just yields a non-rational result.
x^2 + 2 = 0
x^2 = -2
sqrt(x^2) = sqrt(-2)
x = i * sqrt(2) -- or -- x = sqrt(2) * i
Or you can have
x^2 - 2 = 0
x^2 = 2
sqrt(x^2) = sqrt(2)
x = sqrt(2)
If you were to then graph f(x) = sqrt(x), you would find that the graph is only in quadrant I and that at the coordinate (2,x), x is 1.41421 (ca. sqrt(2)).
Now, if you were to graph f(x) = i * sqrt(x), you would find that the graph is only in quadrant III and that at the coordinate (-2,x), x is -1.41421 (ca. i * sqrt(2)).
Therefore, since f(x) is equivalent to a negative-negative number, both can be changed to positive (at the removing of i), and you will have the same answer. There you go. Both equations yield the same answer, just in different ways of thinking.
x^2 + 2 = 0
x^2 = -2
sqrt(x^2) = sqrt(-2)
x = i * sqrt(2) -- or -- x = sqrt(2) * i
Or you can have
x^2 - 2 = 0
x^2 = 2
sqrt(x^2) = sqrt(2)
x = sqrt(2)
If you were to then graph f(x) = sqrt(x), you would find that the graph is only in quadrant I and that at the coordinate (2,x), x is 1.41421 (ca. sqrt(2)).
Now, if you were to graph f(x) = i * sqrt(x), you would find that the graph is only in quadrant III and that at the coordinate (-2,x), x is -1.41421 (ca. i * sqrt(2)).
Therefore, since f(x) is equivalent to a negative-negative number, both can be changed to positive (at the removing of i), and you will have the same answer. There you go. Both equations yield the same answer, just in different ways of thinking.
Hey, finally someone I can talk with about this stuff. 
I know what you mean, but removing the i in your last function makes a 'totally' different function... in my opinion.
"x = i * sqrt(2) -- or -- x = sqrt(2) * i"
That is exacly the same, for a*b = b*a, I think you wanted to add a '-' to the second one
I know what you mean, but removing the i in your last function makes a 'totally' different function... in my opinion.
"x = i * sqrt(2) -- or -- x = sqrt(2) * i"
That is exacly the same, for a*b = b*a, I think you wanted to add a '-' to the second one
Hey, finally someone I can talk with...
Yay!
but removing the i in your last function...
Well, what I meant by that was something a bit different that the way you interpreted it. Take, for example, x = 23. This yields the same result as -x = -23: both sides are multiplied by i^2, therefore you can divide and simplify.
You're right, f(x) = i * sqrt(2) is the same thing as f(x) = sqrt(2) * i. I just put one in standard form.
Yay!
but removing the i in your last function...
Well, what I meant by that was something a bit different that the way you interpreted it. Take, for example, x = 23. This yields the same result as -x = -23: both sides are multiplied by i^2, therefore you can divide and simplify.
You're right, f(x) = i * sqrt(2) is the same thing as f(x) = sqrt(2) * i. I just put one in standard form.
