Hello all
Hello! 
I'm a litle bit intoxicated! In other words, drunk! What's up?
Poll: Is this the best forum in the world?
1. Yes
2. Yes yes
I'm a litle bit intoxicated! In other words, drunk! What's up?Poll: Is this the best forum in the world?
1. Yes
2. Yes yes
i^1/3 + C
Hell, that's easy. It's 1. Why? Because the process of getting the base zero is nullified if you divide it by itself. Q.E.D. sloppily.
I got one for ya though.
∫e^x^3
Bring it on.
I got one for ya though.
∫e^x^3
Bring it on.
I know it's one - it just looks funny when it's not superscripted.
Is that INT (e^x)^3 dx or INT e^x^3 dx? I would hope it's the first one because I don't think the second one can be solved.
The first one is e^(3x)/3.
The first one is e^(3x)/3.
The math doesn't fit in my head... I push it in, but it keeps popping out...
(written on the table by a hapless student)
(written on the table by a hapless student)
Second one can't be solved with "normal" functions. That's why I asked if he was gamma-compatible, 'cause you can rewrite it with Eulers Gamma-function (don't ask, and I won't need to explain).
The second one. Or, if you want it rewritten for clarity, ∫e^(x^3) dx
I ask you, what can't Euler do?
I ask you, what can't Euler do?
