The Dink Network

Here's a puzzle I'm stuck on, anyone have an answer? Just for fun

Can you move one line to make this equation true?
XXII ÷ VII = III
(and it's underlined, dunno if that counts as another line to move).
(Edit: sans serif!)

All I can come up with is XXII ÷ VII ≠ II, but that might be cheating

And here's one I did manage to answer:

Can you change the numerals ninety-nine into twenty-five by moving two lines?

You could remove the first I in XXII...

It's one of those tricks where you use matchsticks.

XXI÷ VII = III^I

(The last I goes slightly to the upper-right of III, making it 3 to the power of 1)

Sigh, nerds.

Hah, nice

Hmm. The answer given was to move the last line on top of the other two, like so:

XXII ÷ VII = π
(22 ÷ 7 = 3.14)

I like Vukodlak's solution better. I mean 22/7 is only accurate to the first two decimals.

I mean we all know that π = 3.1415926535 8979323846 2643383279 5028841971 6939937510 5820974944 5923078164 0628620899 8628034825 3421170679 8214808651 3282306647 0938446095 5058223172 5359408128 4811174502 8410270193 8521105559 6446229489 5493038196 4428810975 6659334461 2847564823 3786783165 2712019091 4564856692 3460348610 4543266482 1339360726 0249141273 7245870066 0631558817 4881520920 9628292540 9171536436 7892590360 0113305305 4882046652 1384146951 9415116094 3305727036 5759591953 0921861173 8193261179 3105118548 0744623799 6274956735 1885752724 8912279381 8301194912 9833673362 4406566430 8602139494 6395224737 1907021798 6094370277 0539217176 2931767523 8467481846 7669405132 0005681271 4526356082 7785771342 7577896091 7363717872 1468440901 2249534301 4654958537 1050792279 6892589235 4201995611 2129021960 8640344181 5981362977 4771309960 5187072113 4999999 and so on.

^
copied that from calculator

My calculator doesn't say all those numbers, I feel so much less special now thanks Hellfire with numbers geesh... err (But then again I may have throw it at the wall and it just has funny symbols and blank spaces now) *grin*

I wouldn't exactly say the equation is "true" by saying 22/7=π...

No calculator in the world has that many numbers.

Computers can... You can write software to output as many digits as you want.

You need something like this to get good results, though.

Don't you think 5 trillion digits is slight overkill?

You can get up to 32 million digits using SuperPi relatively easily. My ancient laptop calculated 16 million digits in 21 minutes the other day. Posting that many digits would already be a severe break of forum etiquette I think. And if you really feel you need more digits you can download the first trillion digits of pi here... Though I really wonder who would want that to clutter his HD, unpacked that would be almost a terabyte of data...

I am kind of surprised nobody noticed I used the Feynman point in my value for π...

It depends on if you use long-scale trillion or short-scale trillion. In short scale (1,000,000,000,000), it is just under a terabyte, but according to one of my stubborn friends, he believes 1 trillion = 1,000,000,000,000,000,000

you have friends

I thought the use of short scale or long scale depends on your language. And English just uses short scale as far as I know. It is always a bit of a nuisance for me as Dutch uses long scale, so values of over a billion (short scale) don't readily translate between the languages. So in this case I meant 1 trillion (short scale) or 1 billion (long scale).