math puzzle
in a recent poll of moviegoers, 7 out of 10 women said they would recommend the movie to a friend, but only 4 of 10 men agreed. based on this information, what is the probability that the person is a man, given that the person did not like the movie?
Ummm...Interesting.
Nice problem.
Applying Bayes' Theorem and Conditional Probability, the probability that the person is a man, given that the person did not like the movie = 2/3 or 0.67.
Applying Bayes' Theorem and Conditional Probability, the probability that the person is a man, given that the person did not like the movie = 2/3 or 0.67.
But you assume a prior of .5. It sounds like a chick flick. Then there would be more women than men and the probability would be < 2/3!
Someone is right. To solve this problem, you need more data(the probability for your friend to be a man/woman).
it doesnt say if the poll is of the entire audience but if you assume the poll is of an equal part of men and women yes its 2/3 but i like your answer that if more women like the movie its probably a "chick flick" so the sample is of a lot more women than men, i have to agree so you both win headless duck pins
anyway here is my answer: 3 in 10 women did not like the movie, 6 in 10 men did not like the movie. so thats 9 people who did not like the movie. so the probability is 6 in 9 that the person who didnt like the movie is a man. = 2/3
the information of the women is irrelevant to the answer. the probability is that 4 out of 10 wouldn't like th movie, given that they are male.
Dudes, isn't it, like, the holidays? Get out, relax, drink a beer, visit some friends, make D-mods, DON'T DO MATH!
besides, i want to see what you guys think of my answer
3 out of 10 women don't like it, 6 out of 10 men don't like it. Therefore the odds are 2 to 1 that the "I don't like it vote" came from a man.
July 7th 2009, 09:05 PM
nononoq
sry i kinda withdraw my commentt, math maybe aint that uselezz and may eben be funz0rz, but theyr uselezz still 
